Strategy II

For Campus Setting: Find The Density Radius= 3 times SQRT(project Site in sqft). 1 acre=  43560 sqft. Identifu all buildings and parcel within Density radius.

Example: 2 acres = 87,120  s.f. and it’s square root is 295 x 3 = 885

This is the radius that you will use to determine the TOTAL building square footage within the circle with the 885 foot radius. Total these and then divide by the total acres within the circle to get the average density. Example: Buildings within 885 ft. radius         Parcels within 885 ft. radius

Parcels and Building sizing within the Density Radius area

Building Sqft                                 Project and Adjacent

100,000 (project building)                                    87,120 (project site)

10,000 s.f.                                                                        30,000

15,000 s.f.                                                                        45,000

20,000 s.f.                                                                        60,000

12,000 s.f.                                                                        36,000

4,000 s.f.                                                                          4,000

159,000 s.f.                                                                                  262,120 s.f.

To get the 885’ radius circle area in acres, divide 262,120s.f./43,560=6.0 acres

159,000s.f/6.0=26,500 which is <60,000 so does not meet the credit requirements.